Alric Aneron wrote:

hello, I have a python code that recieves two result objects from two different ZSQL methods. I need to join them (sort of like UNION). I can't do result1+result2, otherwise it raises an exception that the + operator isn't supported. When I try to do this (read below, I explained what i've done if you are lazy to read the code) result1 = context.zsqlmethod1() result2 = context.zsqlmethod2() if (len(result1) == 0): return result2 row1 = 0 row2 = len(result1) + 1 col = 0 for r in result2: col = 0 if (context.duplicateExists(result1, result2[row1][0]) == -1): result1[row2][col] = result2[row][col] col = col + 1 row1 = row1 + 1 row2 = row2 + 1

return result1

Basically, it loops through the rows and columns of result2 and adds them to the end of th e result 1. However it for some reason raises "index out of range" and says that assigning result1[0][0]=result2[0][0] (if there is an element in both of them) is illegal because: *Error Value: object does not support item or slice assignment *I realize that in most programming languages you can't add them to result1 without resizing it first, but I can't find much documentaiton on member functions of the result object, so I can't resize it. I am completely stuck, I've tried everything, spent so much time on it, can anyone please help save my sanity :P

Thanks in advance guys! I really appreciate it.

------------------------------------------------------------------------ Y <http://pa.yahoo.com/*http://us.rd.yahoo.com/evt=37474/*http://promo.yahoo.com/broadband/%20>

Alric, The merging of two zsql result sets is easy - here's one way: newResults = [] for r in resultset1: newResults.append( r ) for r in resultset2: newResults.append( r ) return newResults. David

At Friday 30/12/2005 14:32, Alric Aneron wrote:

I have a python code that recieves two result objects from two different ZSQL methods. I need to join them (sort of like UNION). I can't do result1+result2, otherwise it raises an exception that the + operator isn't supported.

This is *untested* but looking at the Results constructor, it does not use its data argument in any way (just stores it in the instance). If you are *sure* both results have the same columns in the same position and all are the same type and size and..., you could do: R1._data = R1._data + R2._data (in a product or external method) Or, create a new instance: Results((R1.__items__, R1._data + R2._data)) Gabriel Genellina Softlab SRL