[Zope] file upload from python script

Tue, 04 Sep 2001 10:18:51 +0000

Hi!

>For me, it's easier in pure Python, but I upload the data in the filesystem
>(not in ZODB)
>Anyway, you can get the uploaded content (not the file path) with the 
>"read"
>method.

No, I tried that. The read()-Method stops the first time it encounters 
chr(0), so when I try to upload my file like
TargetFolder.manage_addFile(NewDocumentName,open(DocumentPath,'r').read()) 
it will be only 6 bytes big.

Funny thing is, if I upload it from DTML, everything works fine and I get 
the full 19K.

I copy the two pages again, that do the upload, because I have some 
questions about them. Obviously, DoUpload receives a parameter "DateiName" 
which is  n o t  a string, because it has an attribute ".filename". So my 
general problem can be reduced to 2 questions:

1. what is the name of the class "DateiName" is an instance of?
2. How can I convert a string that denotes a path into an instance of this 
class?

By the way: is there a run-time-type-identification in python (some function 
that takes an object as arg and returns the name of its class)?

DTML-Document "index_html":

<html>
<form action="DoUpload" enctype="multipart/form-data" method="post">
<input type="file" name="DateiName">
<input type=submit value="upload"></td></tr>
</form>
</html>

DTML-Method "DoUpload":

<html>
<dtml-let fname="_.string.split(DateiName.filename,'\\')[-1]">
<dtml-with upload>
<dtml-if "_.has_key(fname)">
<dtml-call "_[fname].manage_upload(DateiName)">
<dtml-else>
<dtml-call "manage_addFile(fname,DateiName)">
</dtml-if>
<form action="upload/<dtml-var fname>" method="post">
<input type="submit" value="view">
</form>
</dtml-with>
</dtml-let>
</html>

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