in the method (probably a python script) dealing with the upload use the following I patched it from several of my methods. It is not tested but it should give you the idea Robert Call this function as a the action of a file upload form. If it is in a python script just leave out the def part, and give the script the parameter file. def manage_addMyFile ( self, file ) : """ add file """ import os if hasattr(file,'filename'): filename=file.filename title=filename id=filename[max(string.rfind(filename, '/'), string.rfind(filename, '\\'), string.rfind(filename, ':'), )+1:] if(file): if(os.path.splitext(filename)[1] in ['.jpg', '.gif']): self.manage_addImage(id, title, file) if other extention .... ----- Original Message ----- From: Mark Spencer To: zope@zope.org Sent: Monday, March 25, 2002 2:46 AM Subject: [Zope] How to upload files and create file objects from DTML page? I want to have a normal DTML page for users that allows them to upload and download files (without needing to use the management interface). The downloading and display of files is fine, but I cant figure out the zope/python code to create a new file object and store an uploaded file. The files could be upto ~60MB in size, and can be zip or doc files etc. Has anyone seen suitable sample code for this?