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AW: [Zope] Understanding dtml and/or its variables
by Bartakovic, Damir 22 Feb '01

22 Feb '01

Thanks Dieter, exactly what I was searching for! > Damir Bartakovic writes: > > I am using ZnolkSQLWizard and it creates output like > > <INPUT TYPE="TEXT" NAME="table.name"> ... > > > > Now I am trying to force the user not to leave the field blank. > > Usually it works with <dtml-unless "somevariable"> ... once again! > > ....</dtml-unless> > > > > but with <dtml-unless "table.name"> ... I get the error: > > Error Type: NameError > > Error Value: table (The Traceback is at the end) > > > > Like it seems it don't like the '.'? > It likes '.' but interprets it differently: > > Inside "...", you are in the realm of Python expressions. > In Python, the "." is not part of a name (as in DTML) > but it is an operator: the left operand is an object, > the right one a name and the result is the object's attribute > of the given name. > > You can use, e.g. "_['table.name']" to access the object > with name "table.name" from Python. > > The official Zope book and > > URL:http://www.dieter.handshake.de/pyprojects/zope/book/chap3.html > > will tell you more about these issues.

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by lepeshkinan＠aport2000.ru 22 Feb '01

22 Feb '01

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Re: [Zope] creating and using a python object
by Dieter Maurer 22 Feb '01

22 Feb '01

Joh Johannsen writes: > I've got the following python class: > > class TestClass: > def __init__(self): > pass > > def getValue(self): > return 'test' > > How can I create an instance of it, and use it from within a DTML page? You can put it into a product (HowTo on zope.org) or use it in an external method. In both cases, you would need to learn something about Zope security. There is a documentation of Brian about this topic on zope.org. Dieter

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load_site.py doesn't recognize .jpeg
by Paul Winkler 22 Feb '01

22 Feb '01

Hi, Possibly this has been noted and fixed already, but just in case... In Zope 2.2.2, the utilities/load_site.py script doesn't recognize the .jpeg extension - it treats them as plain text files. I solved this by adding one line as shown below. def upload_file(object, f): if os.path.isdir(f): return upload_dir(object, f) dir, name = os.path.split(f) root, ext = os.path.splitext(name) if ext in ('file', 'dir'): ext='' else: ext=string.lower(ext) if ext and ext[0] in '.': ext=ext[1:] if ext == 'jpeg': ext = 'jpg' ### THIS IS THE NEW LINE if ext and globals().has_key('upload_'+ext): if verbose: print 'upload_'+ext, f return globals()['upload_'+ext](object, f) if verbose: print 'upload_file', f, ext call(object.manage_addFile, id=name, file=open(f,'rb')) -- ................. paul winkler .................. slinkP arts: music, sound, illustration, design, etc. web page: http://www.slinkp.com A member of ARMS: http://www.reacharms.com

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LocalFS-0.10.1 and zope-2.3.x - subdirectories not found
by Martin Andrews 22 Feb '01

22 Feb '01

I have tried updating to zope-2.3.0 and LocalFS-0.10.1 but now I cannot access any subdirectories in my local filesystems - I get resource not found errors when I try to traverse them or their contents. I get the same problem with zope-2.3.1b1. Error message and stack trace are: Zope Error Zope has encountered an error while publishing this resource. Resource not found Sorry, the requested Zope resource does not exist. Check the URL and try again. Troubleshooting Suggestions The URL may be incorrect. The parameters passed to this resource may be incorrect. A resource that this resource relies on may be encountering an error. For more detailed information about the error, please refer to the HTML source for this page. If the error persists please contact the site maintainer. Thank you for your patience. Traceback (innermost last): File /dsk/1/tmp/makeme23671/Zope-2.3.1b1-src/lib/python/ZPublisher/Publish.py, line 222, in publish_module File /dsk/1/tmp/makeme23671/Zope-2.3.1b1-src/lib/python/ZPublisher/Publish.py, line 187, in publish File /dsk/1/tmp/makeme23671/Zope-2.3.1b1-src/lib/python/Zope/__init__.py, line 221, in zpublisher_exception_hook (Object: files) File /dsk/1/tmp/makeme23671/Zope-2.3.1b1-src/lib/python/ZPublisher/Publish.py, line 162, in publish File /dsk/1/tmp/makeme23671/Zope-2.3.1b1-src/lib/python/ZPublisher/BaseRequest.py, line 338, in traverse File /opt/ngapp/encap/zope-2.3.0/zope/lib/python/Products/LocalFS/LocalFS.py, line 462, in __bobo_traverse__ (Object: files) File /dsk/1/tmp/makeme23671/Zope-2.3.1b1-src/lib/python/ZPublisher/HTTPResponse.py, line 547, in notFoundError NotFound: (see above) -- Martin Andrews mandrews(a)netgenics.com

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How to write a ZClass constructor method in PythonScript?
by Dirksen 22 Feb '01

22 Feb '01

Inside a ZClass A (extended from objectManager), I define another ZClass B, here is what's in the default contstructor dtml method for B: <dtml-with "B.createInObjectManager(REQUEST['id'], REQUEST)"> ... </dtml-with> Well, I rewrite it in PythonScript, and modify the factory and add_form to point to this new method. The script is like: req = context.REQUEST container.B.createInObjectManager(req['id'], req) I think the PythonScript verion is equivalent to the DTML verion. But in the experiment, the PythonScript complains that B is not a attribute of the container, i.e. an instance of ZClass A, while the DTML works fine. Why is the ZClass definition not exposed to PythonScript? Any hints please! Cheers Dirksen __________________________________________________ Do You Yahoo!? Yahoo! Auctions - Buy the things you want at great prices! http://auctions.yahoo.com/

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quick question - database connections in python methods & return types?
by Lee 22 Feb '01

22 Feb '01

Hi there, I have a quick question that I need answered concerning the return types of SQL queries executed in Python methods. I am querying/updating a database using Python methods as follows: -+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+ # make a database connection string try: db_conn = self.MySQL_database_connection() except Exception: return "A connection to the database could not be made. <a href='./'> Recover</a>." try: SQL = "some SELECT query" result=db_conn.query(SQL) except Exception: return "The class could not be created.<a href='./'> Recover</a>." -+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+ When this is executed and I "return result[1]" it outputs the data in a format like: [(1, 16, 9, 1)] * return result[0] gives me: [{'name': 'PRACTICALS', 'type': 's', 'null': None, 'width': None}, {'name': 'TUTORIALS', 'type': 's', 'null': None, 'width': None}, {'name': 'ASSIGNMENTS', 'type': 's', 'null': None, 'width': None}, {'name': 'BONUS', 'type': 's', 'null': None, 'width': None}] - the exact details aren't neccessary here I think. At first I had problems trying to use this data i.e. parse it an store it in an array, list, etc. but I overcome that by by first converting "result" to a string using `result[1]`. I was just wondering how to classify the original return type? It is *not* a list, tuple, array or combination of either so what is it? I'm writing a report on my project you see and I can't say that my method returns an *cough* *cough* value ;-) Thanks very much in advance if you can help. Cheers, Lee

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Virtual Host Monster problems
by John Morton 22 Feb '01

22 Feb '01

I'm having some difficulties getting the virtual host monster object doing what it ought to be doing. My set up is Apache doing proxy pass thing to the magic virtual host monster path names on a Zope 2.2.5 install that's using Site Access 2.0.0b4. What it's suceeding in doing is serving pages from the name virtual URLs; what it's not doing is translating internal page links at all. The wierd thing is that I got the whole thing working without a hitch on a very similar install at home, yesterday. The only differences of note are that this instance of Zope has a few more products installed (can't tell you which at this stage) and that the home install was a fresh name virtual setup, where as the problem one started out as a SiteRoot name virtual setup and is being converted to use the Virtual Host Monster method. So, has anyone encountered this problem before? Does anyone have any idea where I should start trying to fix this problem? John

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Problem using AUTHENTICATED_USER
by Jérôme Loisel 21 Feb '01

21 Feb '01

Hi folks! I am somewhat unable to check whether or not the user has manager access to some object object. The following does not work as expected: <dtml-if "AUTHENTICATED_USER.has_role('Manager', _.getitem('.news'))"> <P>Blah.</P> </dtml-if> Instead of getting a true result if the user has manager acces to the .news item (a folder), I get a true result if the user has manager access to his context. Related question: How do I access AUTHENTICATED_USER from Python? Can anyone point me in the right direction? Thanks, Jérôme Loisel. PS: Shouldn't there be separate mailing lists for different types of users? Content managers probably have different questions from (beginning) developpers... -- Jérôme Loisel Lévinux: GNU/Linux dans les communautés à Lévis

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Re: [Zope] Zope on an IBM S/390
by Philipp Auersperg 21 Feb '01

21 Feb '01

Thanks, Porting the Oracle driver was also was my first thought, I'm glad to your opinion that this should work. Philipp Auersperg phil(a)bluedynamics.com *********** REPLY SEPARATOR *********** On 21.02.2001 at 15:02 Christopher Petrilli wrote: >Howdy :-) > >I no longer work for Digital Creations, and am not sure who would be >responsible for DA issues there. I have had a cursory look at the >DB/2 Python DB-API interface that was written and it seems to be >thread safe, making writing of a high-performance DA much easier. I >would imagine you could actually steal the Oracle DA code for that and >have it up and running in a matter of minutes. > >Good luck. >Chris >-- >| Christopher Petrilli >| petrilli(a)amber.org

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